3x^2+10x-12=3.75

Solution for 3x^2+10x-12=3.75 equation:

3x^2+10x-12=3.75

We move all terms to the left:

3x^2+10x-12-(3.75)=0

We add all the numbers together, and all the variables

3x^2+10x-15.75=0

a = 3; b = 10; c = -15.75;
Δ = b2-4ac
Δ = 102-4·3·(-15.75)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-17}{2*3}=\frac{-27}{6}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+17}{2*3}=\frac{7}{6}
=1+1/6
$